2.25^2+x^2=2x^2

Solution for 2.25^2+x^2=2x^2 equation:

2.25^2+x^2=2x^2

We move all terms to the left:

2.25^2+x^2-(2x^2)=0

We add all the numbers together, and all the variables

-1x^2+5.0625=0

a = -1; b = 0; c = +5.0625;
Δ = b2-4ac
Δ = 02-4·(-1)·5.0625
Δ = 20.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{20.25}}{2*-1}=\frac{0-\sqrt{20.25}}{-2}
=-\frac{\sqrt{}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{20.25}}{2*-1}=\frac{0+\sqrt{20.25}}{-2}
=\frac{\sqrt{}}{-2}
$